(6x^2)+X=180

Solution for (6x^2)+X=180 equation:

(6x^2)+x=180

We move all terms to the left:

(6x^2)+x-(180)=0

a = 6; b = 1; c = -180;
Δ = b2-4ac
Δ = 12-4·6·(-180)
Δ = 4321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{4321}}{2*6}=\frac{-1-\sqrt{4321}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{4321}}{2*6}=\frac{-1+\sqrt{4321}}{12}
$